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જો $\left( {\begin{array}{*{20}{c}}
{189} \\
{35}
\end{array}} \right) + \left( {\begin{array}{*{20}{c}}
{189} \\
x
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
{190} \\
x
\end{array}} \right)\,\,$ હોય તો ,$x\, = \,\,.........$
$34$
$35$
$36$
$37$
Solution
$\left( {\begin{array}{*{20}{c}}
n \\
{r – 1}
\end{array}} \right) + \left( {\begin{array}{*{20}{c}}
n \\
r
\end{array}} \right) = = \left( {\begin{array}{*{20}{c}}
{n + 1} \\
r
\end{array}} \right)\,\,$ પ્રમાણે $\left( {\begin{array}{*{20}{c}}
{189} \\
{35}
\end{array}} \right) + \left( {\begin{array}{*{20}{c}}
{189} \\
{36}
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
{190} \\
{36}
\end{array}} \right)$ મળે
તેથી $\left( {\begin{array}{*{20}{c}}
{189} \\
{35}
\end{array}} \right) + \left( {\begin{array}{*{20}{c}}
{189} \\
x
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
{190} \\
x
\end{array}} \right)\,\,$
આપેલ હોય તો ${\text{x = 36}}$
