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6.Permutation and Combination
medium

જો $\,_nP_r\,\, = \,\,30240$ અને  $\,\left( {\begin{array}{*{20}{c}}
  n \\ 
  r 
\end{array}} \right) = 252\,$ તો $\,(n\,,\,\,r)\,\, = \,\,..........$

A

$(9, 4)$

B

$(10, 5)$

C

$(16, 7)$

D

$(12, 6)$

Solution

$\left( {\begin{array}{*{20}{c}}
  n \\ 
  r 
\end{array}} \right) = \frac{{_n{P_r}}}{{r\,!}}$

$r\,!\, = \,\frac{{30240}}{{252}} = 120 = 5\,!$

$r\, = \,5$

$\left( {\begin{array}{*{20}{c}}
  n \\ 
  5 
\end{array}} \right) = \frac{{n\,!}}{{(n – 5)\,!\,5\,!}} = 252$

$n(n – 1)(n – 2)(n – 3)(n – 4) = 252 \times 120$

$n(n – 1)(n – 2)(n – 3)(n – 4)$

$ = 10.6.2.9.7.4\, = \,10.9.8.7.6\,\,$

$n = 10\,\,\,\therefore \,(n,\,r) = (10,\,5)$

 

Standard 11
Mathematics

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