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6.Permutation and Combination
medium
જો $\,_nP_r\,\, = \,\,30240$ અને $\,\left( {\begin{array}{*{20}{c}}
n \\
r
\end{array}} \right) = 252\,$ તો $\,(n\,,\,\,r)\,\, = \,\,..........$
A
$(9, 4)$
B
$(10, 5)$
C
$(16, 7)$
D
$(12, 6)$
Solution
$\left( {\begin{array}{*{20}{c}}
n \\
r
\end{array}} \right) = \frac{{_n{P_r}}}{{r\,!}}$
$r\,!\, = \,\frac{{30240}}{{252}} = 120 = 5\,!$
$r\, = \,5$
$\left( {\begin{array}{*{20}{c}}
n \\
5
\end{array}} \right) = \frac{{n\,!}}{{(n – 5)\,!\,5\,!}} = 252$
$n(n – 1)(n – 2)(n – 3)(n – 4) = 252 \times 120$
$n(n – 1)(n – 2)(n – 3)(n – 4)$
$ = 10.6.2.9.7.4\, = \,10.9.8.7.6\,\,$
$n = 10\,\,\,\therefore \,(n,\,r) = (10,\,5)$
Standard 11
Mathematics
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