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4-1.Newton's Laws of Motion
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કારની ઝડપ $10\%$ વધારવામાં આવે છે, જો રોડનો ખૂણો અચળ રાખીને ત્રિજયા $20\,m$ માંથી ........ $m$ કરવી પડે.
A$16$
B$18$
C$24.2$
D$30.5$
Solution
$\tan \theta = \frac{{{v^2}}}{{r\,g}}$
$\Rightarrow r \propto {v^2} \,\,\,\,(\theta \,= અચળ)$
$\frac{{{r_2}}}{{{r_1}}} = {\left( {\frac{{{v_2}}}{{{v_1}}}} \right)^2} = {\left( {\frac{{1.1v}}{v}} \right)^2} \,= 1.21$
$\Rightarrow r_2 = 1.21 \times \,r_1 \,= 1.21 \times \,20 = 24.2 \,m$
$\Rightarrow r \propto {v^2} \,\,\,\,(\theta \,= અચળ)$
$\frac{{{r_2}}}{{{r_1}}} = {\left( {\frac{{{v_2}}}{{{v_1}}}} \right)^2} = {\left( {\frac{{1.1v}}{v}} \right)^2} \,= 1.21$
$\Rightarrow r_2 = 1.21 \times \,r_1 \,= 1.21 \times \,20 = 24.2 \,m$
Standard 11
Physics
