English
Hindi
2.Motion in Straight Line
medium

કણનો પ્રવેગ $OA, AB$ અને $BC$ પર અનુક્રમે કેટલો મળે?

A

$1, 0, -0.5$

B

$1, 0, 0.5$

C

$1, 1, 0.5$

D

$1, 0.5, 0$

Solution

$OA  = \frac{{{v_2} – {v_1}}}{t} = \frac{{10 – 0}}{{10}} = 1m/{s^2}$

$OB  = \frac{0}{{10}} = 0$

$BC  = \,\frac{{0 – 10}}{{20}} = -0.5 m/s^2$

Standard 11
Physics

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