English
Hindi
10-2.Transmission of Heat
normal

ગરમ પાણીનું તાપમાન ${60^o}C$ થી ${50^o}C$ થતા $10 \,min$ લાગે છે, અને તાપમાન ${50^o}C$ થી $42^oC$ થતા $10 \,min$ લાગે છે. તો વાતાવરણનું તાપમાન ........ $^oC$  હશે?

A

$5$

B

$10$

C

$15$

D

$20$

Solution

$\Rightarrow \frac{{{\theta _1} – {\theta _2}}}{t} \propto \left[ {\frac{{{\theta _1} + {\theta _2}}}{2} – \theta } \right]$

$\Rightarrow \frac{{60 – 50}}{{10}} \propto \left[ {\frac{{60 + 50}}{2} – \theta } \right]$

$\Rightarrow 1 = K\, [55 -\theta ]\,\,……(i)$

$\Rightarrow \frac{{50 – 42}}{{10}} \propto \left[ {\frac{{50 + 42}}{2} – \theta } \right]$

$\Rightarrow 0.8 = K \,(46 -\theta ) \,\,…..(ii)$

$\Rightarrow \theta = 10^oC$

Standard 11
Physics

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