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1. Electric Charges and Fields
normal
$C_1 = 2\ \mu\ F ,C_2 = 6\ \mu\ F$ અને $C_3 = 4\ \mu\ F$.હોય તો,તંત્રની કુલ ઊર્જા કેટલી થાય?
A
$22 \times {10^{ - 6}}J$
B
$11 \times {10^{ - 6}}J$
C
$\left( {\frac{{32}}{3}} \right)\, \times {10^{ - 6}}J$
D
$\left( {\frac{{16}}{3}} \right)\, \times {10^{ - 6}}J$
Solution
${C_{eq}} = \frac{{{C_1}{C_2}}}{{{C_1} + {C_2}}} + {C_3} = \frac{{2 \times 6}}{8} + 4 = 5.5\,\mu F$
$U = \frac{1}{2}{C_{eq}}.{V^2} = \frac{1}{2} \times 5.5 \times {(2)^2} = 11 \times {10^{ – 6}}\,J$
Standard 12
Physics
