6 દિવસ પછી અવિભંજીત ભાગ 7/8 હોય,તો 10 દિવસ પછ | vedclass

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Question

$N = {N_0}{\left( {\frac{1}{2}} \right)^{t/{T_{1/2}}}}$

$\Rightarrow$ $t = \frac{{{T_{1/2}}{{\log }_e}\left( {\frac{{{N_0}}}{N}} \right)}}{{{{

Vedclass · Accepted Answer

$31/32$

Vedclass · Answer

$N = {N_0}{\left( {\frac{1}{2}} \right)^{t/{T_{1/2}}}}$

$\Rightarrow$ $t = \frac{{{T_{1/2}}{{\log }_e}\left( {\frac{{{N_0}}}{N}} \right)}}{{{{\log }_e}(2)}}$

$\Rightarrow$ $t \propto {\log _e}\frac{{{N_0}}}{N}$

$\Rightarrow$ $\frac{{{t_1}}}{{{t_2}}} = \frac{{{{\left( {{{\log }_e}\frac{{{N_0}}}{N}} \right)}_1}}}{{{{\left( {{{\log }_e}\frac{{{N_0}}}{N}} \right)}_2}}}$ $\frac{6}{{10}} = \frac{{{{\log }_e}(8/1)}}{{{{\log }_e}({N_0}/N)}}$

$\Rightarrow$ ${\log _e}\frac{{{N_0}}}{N} = \frac{{10}}{6}{\log _e}(8) = {\log _e}32$

$\Rightarrow$ $\frac{{{N_0}}}{N} = 32$

અવિભંજીત ભાગ $ = 1 - \frac{1}{{32}} = \frac{{31}}{{32}}$.

$6$ દિવસ પછી અવિભંજીત ભાગ $7/8$ હોય,તો $10$ દિવસ પછી અવિભંજીત ભાગ કેટલો થાય?

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