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11.Thermodynamics
medium
$P-V$ diagram of an ideal gas is as shown in figure. Work done by the gas in process $ABCD$ is

A
$4\,{P_0}{V_0}$
B
$2\,{P_0}{V_0}$
C
$3\,{P_0}{V_0}$
D
${P_0}{V_0}$
Solution
(c) ${W_{AB}} = – \,{P_0}{V_0}$, ${W_{BC}} = 0$ and ${W_{CD}} = 4{P_0}{V_0}$
==> ${W_{ABCD}} = – \,{P_0}{V_0} + 0 + 4{P_0}{V_0} = 3{P_0}{V_0}$
Standard 11
Physics