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11.Thermodynamics
easy
An ideal gas is taken around the cycle $ABCA$ as shown in the $P-V $ diagram. The net work done by the gas during the cycle is equal to

A
$12\,{P_1}{V_1}$
B
$6\,{P_1}{V_1}$
C
$3\,{P_1}{V_1}$
D
$2{P_1}{V_1}$
Solution
(d) Work done $ = \frac{1}{2} \times 2{P_1} \times 2{V_1} = 2{P_1}{V_1}$
Standard 11
Physics
Similar Questions
One mole of a monatomic ideal gas is taken through a cycle $ABCDA$ as shown in the $P-V$ diagram. Column $II$ gives the characteristics involved in the cycle. Match them with each of the processes qiven in Column $I$
Column $I$ | Column $II$ |
$(A)$ Process $A \rightarrow B$ | $(p)$ Internal energy decreases. |
$(B)$ Process $B \rightarrow C$ | $(q)$ Internal energy increases. |
$(C)$ Process $C \rightarrow D$ | $(r)$ Heat is lost. |
$(D)$ Process $D \rightarrow A$ | $(s)$ Heat is gained. |
$(t)$ Work is done on the gas. |