10^{-3} , W of 5000, mathring A light is dir | vedclass

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Question

$=\frac{\mathrm{n} / \Delta \mathrm{t}}{\mathrm{N} / \Delta \mathrm{t}} 	imes 100$      $...(1)$
$\because \mathrm{I}=\frac

Vedclass · Accepted Answer

$.04$

Vedclass · Answer

$=\frac{\mathrm{n} / \Delta \mathrm{t}}{\mathrm{N} / \Delta \mathrm{t}} 	imes 100$      $...(1)$
$\because \mathrm{I}=\frac{\mathrm{ne}}{\Delta \mathrm{t}}$
$\frac{\mathrm{n}}{\Delta \mathrm{t}}=\frac{\mathrm{I}}{\mathrm{e}}=\frac{0.16 	imes 10^{-16}}{1.6 	imes 10^{-19}}$
$	herefore \frac{\mathrm{n}}{\Delta \mathrm{t}}=10^{12}$        $...(2)$
and $\quad \mathrm{W}=\frac{\mathrm{N}}{\Delta \mathrm{t}} \frac{\mathrm{hc}}{\lambda}$
$	herefore \frac{\mathrm{N}}{\Delta \mathrm{t}}=\frac{\mathrm{W} \lambda}{\mathrm{hc}}=\frac{10^{16}}{4}$        $...(3)$
Persentage $=\frac{10^{12}}{10^{16}} 	imes 4 	imes 100$
$[	ext { from eq. }(1),(2) 	ext { and }(3)]$
Persentage $=0.04 \%$

$10^{-3} \, W$ of $5000\, \mathring A $ light is directed on a photoelectric cell. If the current in the cell is $0.16 \mu A$, the percentage of incident photons which produce photoelectrons, is.......$\%$

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