In a photoemissive cell with executing wavelength $\lambda $, the fastest electron has speed $v.$ If the exciting wavelength is changed to $\frac{{3\lambda }}{4}$, the speed of the fastest emitted electron will be

  • [AIPMT 1998]
  • [AIIMS 2008]
  • [JEE MAIN 2016]
  • A

    $v\;{(3/4)^{1/2}}$

  • B

    $v\;{(4/3)^{1/2}}$

  • C

    $ < v\;{(4/3)^{1/2}}$

  • D

    $ > v\;{(4/3)^{1/2}}$

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  • [IIT 2013]

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