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5.Work, Energy, Power and Collision
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$A$ particle is rotated in a vertical circle by connecting it to $a$ light rod of length $l$ and keeping the other end of the rod fixed. The minimum speed of the particle when the light rod is horizontal for which the particle will complete the circle is
A
$\sqrt {g{\text{l}}} $
B
$\sqrt {2g{\text{l}}} $
C
$\sqrt {3g{\text{l}}} $
D
none
Solution

$\frac{1}{2} m v^{2}+m g l=\frac{1}{2} \mu^{2},$ for $u_{\min } v=0$
$u_{\min }=\sqrt{2 g l}$
Standard 11
Physics
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