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6.System of Particles and Rotational Motion
normal
$A$ uniform rod of mass $m$ and length $l$ hinged at its end is released from rest when it is in the horizontal position. The normal reaction at the hinge when the rod becomes vertical is :
A
$\frac{{Mg}}{2}$
B
$\frac{{3Mg}}{2}$
C
$\frac{{5Mg}}{2}$
D
$2\, Mg$
Solution

Loss in $P.E.$ $=$ gain in $K.E.$
or $\quad \operatorname{mg} \frac{l}{2}=\frac{1}{2} \mathrm{I} \omega^{2}$
or $\quad \mathrm{mg} l=\frac{\mathrm{m} l^{2}}{3} \omega^{2}$
or $\frac{3 \mathrm{g}}{l}=\omega^{2}$
$\mathrm{F}-\mathrm{mg}=\mathrm{m} \frac{l}{2} \omega^{2}$
or $\quad \mathrm{F}=\mathrm{mg}+\mathrm{m} \frac{l}{2} \omega^{2}$
$\mathrm{F}=\mathrm{mg}+\mathrm{m} \frac{l}{2} \frac{3 \mathrm{g}}{l}=\frac{5 \mathrm{mg}}{2}$
Standard 11
Physics
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