A circular disc has a mass of 1 kg | vedclass

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Question

Work done in rotating disc $=$ change in $m=1 k g$

$x=0.4$

So, final $\mathrm{KE}$ is zero as it stops, so work will be Initial $L=K . E=\frac{1

Vedclass · Accepted Answer

$158$

Vedclass · Answer

Work done in rotating disc $=$ change in $m=1 k g$

$x=0.4$

So, final $\mathrm{KE}$ is zero as it stops, so work will be Initial $L=K . E=\frac{1}{2} I \omega^{2}$

as,

$\omega=2 \pi f$

$f=10 r e v / s e c$

$\omega=20 x ightarrow 62.8$

$I=\frac{M R^{2}}{2}=0.08$

so, work done $=\frac{1}{2} 	imes 0.08 	imes(62.8)^{2}$

$158\, J$

A circular disc has a mass of $1\ kg$ and radius $40\ cm$. It is rotating about an axis passing through its centre and perpendicular to its plane with a speed of $10\ rev/s$. The work done in joules in stopping it would be ...... $J$

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