A particle starts from point (0m, 8m) and moves with uniform velocity of 3, hat{i} ,m/s . After 5 se

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3-2.Motion in Plane

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$A$ particle starts from the point $(0m, 8m)$ and moves with uniform velocity of $3\, \hat i \,m/s$. After $5$ seconds, the angular velocity of the particle about the origin will be :

A

$\frac{8}{{289}} \,rad/s$

B

$\frac{3}{{8}} \,rad/s$

C

$\frac{24}{{289}} \,rad/s$

D

$\frac{8}{{17}} \,rad/s$

Solution

at $t=5$ sec, $x=3 \times 5=15 \mathrm{m}$

$y=8$

$\omega=\frac{v \sin \theta}{r} \Rightarrow \omega=\frac{3}{\sqrt{289}} \times \frac{8}{\sqrt{289}}$

$\omega=\frac{24}{289} r a d / \mathrm{sec}$

Standard 11

Physics

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