Gujarati
Hindi
11.Thermodynamics
normal

$1\  cc$ of water at its boiling point $(100^o\  C)$ is converted into steam by supplying it $540\  calories$ of heat the volume of steam is $1671\  cc$. If atmospheric pressure is $1.013 × 10^ 5\  Nm^{-2}$ and $J = 4.18\  joule/cal$ the approximate value of heat that is required in overcoming the molecular attraction is ........ $cal$

A

$110$

B

$500$

C

$40$

D

$0$

Solution

Energy spent in overcoming inter$-$molecular forecs.

$\Delta U=\Delta Q-\Delta W$

$\Delta Q-P\left(V_{2}-V_{1}\right)$

$=540-\frac{1.013 \times 10^{5}(1671-1) \times 10^{-6}}{4.2}$

$\Rightarrow 500 \mathrm{cal}$

Standard 11
Physics

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