11.Thermodynamics
normal

An ideal gas heat engine operates in a Carnot's cycle between ${227^o}C$ and ${127^o}C$. It absorbs $6 × 10^4 \,J$ at high temperature. The amount of heat converted into work is ....

A

$4.8 \times {10^4}\,J$

B

$3.5 \times {10^4}\,J$

C

$1.6 \times {10^4}\,J$

D

$1.2 \times {10^4}\,J$

Solution

(d) $\eta = 1 – \frac{{{T_2}}}{{{T_1}}} = 1 – \frac{{400}}{{500}} = \frac{1}{5}$ 

$\because \;\eta  = \frac{W}{Q}$

==> $\frac{1}{5} = \frac{W}{Q}$
==> $W = \frac{Q}{5} = \frac{6}{5} \times {10^4} = 1.2 \times {10^4}\,J$

Standard 11
Physics

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