$cot 5^o$ -$tan5^o$ -$2$ $tan10^o$ -$4$ $tan 20^o$ -$8$ $cot40^o$ = 

  • A

    $0$

  • B

    $4\tan {40^o}$

  • C

    $8\tan {40^o}$

  • D

    $8\cot {40^o}$

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  • [IIT 1977]