$cot 5^o$ -$tan5^o$ -$2$ $tan10^o$ -$4$ $tan 20^o$ -$8$ $cot40^o$ is equal to
$cot 5^o$ -$tan5^o$ -$2$ $tan10^o$ -$4$ $tan 20^o$ -$8$ $cot40^o$ is equal to
- A
$0$
- B
$4\tan {40^o}$
- C
$8\tan {40^o}$
- D
$8\cot {40^o}$
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