$BCl_3$ does not exist as dimer but $BH_3$ exist as dimer $(B_2H_6)$ becuase
$BCl_3$ does not exist as dimer but $BH_3$ exist as dimer $(B_2H_6)$ becuase
- A
Chlorine is more electronegative than hydrogen
- B
There is $p\pi -p \pi $ back bonding in $BCl_3$ but does not contain such multiple bonding
- C
Large sized chlorine atoms do not fit in between the small boron atoms whereas small sized hydrogenatoms get fitted between boron atoms
- D
none of these
Similar Questions
Given below are two statements :
Statement $I:$ Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement $II:$ The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below :
Given below are two statements :
Statement $I:$ Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement $II:$ The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below :
- [JEE MAIN 2023]
The structure of diborane contains:
The structure of diborane contains:
Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively, $BeF_6^{3-}$ is not formed.
Reason : In case of $Be$, no vacant $d-$ orbitals are present in its outermost shell.
Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively, $BeF_6^{3-}$ is not formed.
Reason : In case of $Be$, no vacant $d-$ orbitals are present in its outermost shell.
- [AIIMS 2015]
Which of the following is not true about potash alum
Which of the following is not true about potash alum
The incorrect statement regarding above reactions is
$\mathop {Al}\limits_{Metal} \xrightarrow{{HCl(aq.)}}'X' + Gas\,'P'$
$\mathop {Al}\limits_{metal} \xrightarrow[{ + {H_2}O}]{{NaOH\,(aq.)}}'Y' + Gas\,'Q'$
The incorrect statement regarding above reactions is
$\mathop {Al}\limits_{Metal} \xrightarrow{{HCl(aq.)}}'X' + Gas\,'P'$
$\mathop {Al}\limits_{metal} \xrightarrow[{ + {H_2}O}]{{NaOH\,(aq.)}}'Y' + Gas\,'Q'$