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p-Block Elements - I
hard
The formation of molecular complex $BF_3 - NH_3$ results in a change in hybridization of boron
A
from $sp^2$ to $dsp^2$
B
from $sp^2$ to $sp^3$
C
from $sp^3$ to $sp^2$
D
from $sp^3$ to $sp^3d$
(AIEEE-2012)
Solution
In $BF_3, B$ is $sp^2$ hybridized with one empty $P_z$ orbital. The empty $P_z$ orbital of $BF_3$ can be filled by lone pair of molecules . such as $NH_3$ . When this occurs a tetrahedral molecule or ion is formed which is $sp^3$ hybridized
Standard 11
Chemistry
