Average force necessary to stop a hammer with momentum p Ns in 0.5 s is .......... N

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4-1.Newton's Laws of Motion

easy

The average force necessary to stop a hammer with momentum $p\; Ns$ in $0.5\; s$ is .......... $N$

A

$2 p$

B

$p$

C

$4 p$

D

$\frac{p}{2}$

Solution

(a)

Force $=$ change in momentum $/$ time

here, initial momentum $=p$

if hammer comes to rest, final momentum $=0$

change in momentum $=p-0=p$

time $=0.5\,s$

Average force $= p / 0.5=2 p N$

Average force is $2 p$ Newton.

Standard 11

Physics

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