Gujarati
Hindi
9-1.Fluid Mechanics
normal

A $U$ tube contains water and methylated spirit separated by mercury . The mercury columns in the two arms are at the same level with $10\,cm$ of water in one arm and $12.5\,cm$ of spirit in the other as shown in figure. The relative density of the spirit is

A

$0.6$

B

$0.8$

C

$1.0$

D

$1.25$

Solution

Refer figure.

As the mercury columns in the two arms of

$U$ tube are at the same level, therefore

Pressure due to water $=$ Pressure due to

spirit column $\rho_{w} h_{w} g=\rho_{s} h_{s} g$

$\rho_{\mathrm{s}}=\frac{\mathrm{h}_{\mathrm{w}}}{\mathrm{h}_{\mathrm{s}}} \rho_{\mathrm{w}}$

$\therefore$ Relative density of spirit

$=\frac{\rho_{\mathrm{s}}}{\rho_{\mathrm{w}}}=\frac{\mathrm{h}_{\mathrm{w}}}{\mathrm{h}_{\mathrm{s}}}=\frac{10 \mathrm{cm}}{12.5 \mathrm{cm}}=0.8$

Standard 11
Physics

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