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9-1.Fluid Mechanics
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A $U$ tube contains water and methylated spirit separated by mercury . The mercury columns in the two arms are at the same level with $10\,cm$ of water in one arm and $12.5\,cm$ of spirit in the other as shown in figure. The relative density of the spirit is

A
$0.6$
B
$0.8$
C
$1.0$
D
$1.25$
Solution

Refer figure.
As the mercury columns in the two arms of
$U$ tube are at the same level, therefore
Pressure due to water $=$ Pressure due to
spirit column $\rho_{w} h_{w} g=\rho_{s} h_{s} g$
$\rho_{\mathrm{s}}=\frac{\mathrm{h}_{\mathrm{w}}}{\mathrm{h}_{\mathrm{s}}} \rho_{\mathrm{w}}$
$\therefore$ Relative density of spirit
$=\frac{\rho_{\mathrm{s}}}{\rho_{\mathrm{w}}}=\frac{\mathrm{h}_{\mathrm{w}}}{\mathrm{h}_{\mathrm{s}}}=\frac{10 \mathrm{cm}}{12.5 \mathrm{cm}}=0.8$
Standard 11
Physics
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