Gujarati
Hindi
13.Oscillations
medium

A $5\, kg$ collar is attached to a spring of spring constant $500\, Nm^{-1}$. It slides without friction over a horizontal rod. The collar is displaced from its equillibrium position by $10\, cm$ and released. The time period of oscillation is

A

$\frac{\pi }{5}\,s$

B

$\frac{\pi }{2}\,s$

C

$\pi \,s$

D

$2\pi \,s$

Solution

$\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{K}}}=\sqrt{\frac{5}{500}}=\frac{2 \pi}{10}=\frac{\pi}{5} \mathrm{s}$

Standard 11
Physics

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