A bob of mass m attached to an inextensible s | vedclass

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Question

The direction of $\vec{\omega}$ vector

is always $\perp^f$ to the plane

containing $\quad \overrightarrow{\mathrm{r}} \& \overrightarrow{\ma

Vedclass · Accepted Answer

Angular momentum changes in direction but not in magnitude

Vedclass · Answer

The direction of $\vec{\omega}$ vector

is always $\perp^f$ to the plane

containing $\quad \overrightarrow{\mathrm{r}} \& \overrightarrow{\mathrm{v}}, \quad$ as

shown in fig. (at any instant).

Angular momentum

$\overrightarrow{\mathrm{L}}=\mathrm{I} \vec{\omega}$

Obviously, $\overrightarrow{\mathrm{L}}$ changes, as

$\vec{\omega}$ changes in direction but

$\overrightarrow 	au   \Uparrow d\overrightarrow 	heta  $

$	herefore$ No work is done by torque due to weight of bob.

So $|\vec{\omega}|=$ constant

or $|\overrightarrow{\mathrm{L}}|=$ constant

A $bob$ of mass $m$ attached to an inextensible string of length $l$ is suspended from a vertical support. The $bob$ rotates in a horizontal circle with an angular speed $\omega\, rad/s$ about the vertical. About the point of suspension

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