A 0.1, M solution of HF is 1% ionized. Kₐ

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6-2.Equilibrium-II (Ionic Equilibrium)

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A $0.1\, M$ solution of $HF$ is $1\%$ ionized. What is the $K_a$

A

${10^{ - 5}}$

B

${10^{ - 4}}$

C

$3 \times {10^{ - 5}}$

D

$3 \times {10^{ - 4}}$

Solution

$\mathrm{K}_{\mathrm{a}}=\frac{\mathrm{C} \alpha^{2}}{1-\alpha}=\frac{0.1\left(\frac{1}{100}\right)^{2}}{1-0.01}=10^{-5}$

Standard 11

Chemistry

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