A $0.1\, M$ solution of $HF$ is $1\%$ ionized. What is the $K_a$
${10^{ - 5}}$
${10^{ - 4}}$
$3 \times {10^{ - 5}}$
$3 \times {10^{ - 4}}$
A weak acid is $ 0.1\% $ ionised in $0.1\, M $ solution. Its $pH$ is
Calculate $pH$ of $0.02$ $mL$ $ClC{H_2}COOH$. Its ${K_a} = 1.36 \times {10^{ - 3}}$ calculate its $pK_{b}$,
Derive ${K_w} = {K_a} \times {K_b}$ and ${K_w} = p{K_a} \times p{K_b}$ for weak base $B$ and its conjugate acid ${B{H^ + }}$.
At $298\,K$ a $0.1 \,M $ $C{H_3}COOH$ solution is $ 1.34\%$ ionized. The ionization constant ${K_a}$ for acetic acid will be
The $pH$ of $0.1$ $M$ solution of cyanic acid $(HCNO)$ is $2.34$. Calculate the ionization constant of the acid and its degree of ionization in the solution.