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6-2.Equilibrium-II (Ionic Equilibrium)
medium
Degree of dissociation of $0.1\,N\,\,C{H_3}COOH$ is (Dissociation constant $ = 1 \times {10^{ - 5}}$)
A
${10^{ - 5}}$
B
${10^{ - 4}}$
C
${10^{ - 3}}$
D
${10^{ - 2}}$
Solution
(d) Degree of dissociation $\alpha$ = ?
Normality of solution = $0.1 \,N$ $ = \frac{1}{{10}}N$
Volume = $10$ litre
Dissociation constant $K = 1 \times {10^{ – 5}}$
$K = \frac{{{\alpha ^2}}}{V}$; $\alpha = \sqrt {KV} $ $ = \sqrt {1 \times {{10}^{ – 5}} \times 10} $ ;
$\alpha = 1 \times {10^{ – 2}}$
Standard 11
Chemistry
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