A 5 metre long wire is fixed to ceiling. A weight of 10, kg is hung at lower end and is 1 metre abov

English

Gujarati

Hindi

8.Mechanical Properties of Solids

medium

A $5$ metre long wire is fixed to the ceiling. A weight of $10\, kg$ is hung at the lower end and is $1$ metre above the floor. The wire was elongated by $1\, mm$. The energy stored in the wire due to stretching is ......... $ joule$

A

$0$

B

$0.05$

C

$100$

D

$500$

Solution

(b) $W = \frac{1}{2} \times F \times l = \frac{1}{2}mgl$

$ = \frac{1}{2} \times 10 \times 10 \times 1 \times {10^{ – 1}} = 0.05\;J$

Standard 11

Physics

Share

Similar Questions

A steel rod of length $\ell$, cross sectional area $A$, young's modulus of elasticity $Y$, and thermal coefficient of linear expansion $'a'$ is heated so that its temperature increases by $t\,^oC$. Work that can be done by rod on heating will be

hard

What is called elastic potential energy ? Write its different formulas.

medium

Work done by restoring force in a string within elastic limit is $-10 \,J$. Maximum amount of heat produced in the string is ………. $J$

easy

Two steel wires having same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is $1: 4,$ the ratio of their diameters is

medium

(JEE MAIN-2020)

Given : $\sigma$ is the compressibility of water, $\rho$ is the density of water and $K$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $‘h’$ metre deep ?

hard