- Home
- Standard 11
- Physics
14.Waves and Sound
easy
A $1 cm$ long string vibrates with fundamental frequency of $256\, Hz$. If the length is reduced to $\frac{1}{4}cm$ keeping the tension unaltered, the new fundamental frequency will be
A
$64$
B
$256$
C
$512$
D
$1024$
Solution
(d) $n \propto \frac{1}{l}$==> $\frac{{{n_2}}}{{{n_1}}} = \frac{{{l_1}}}{{{l_2}}}$
==> ${n_2} = \frac{{{l_1}}}{{{l_2}}}{n_1} = \frac{{1 \times 256}}{{1/4}} = 1024Hz$
Standard 11
Physics
Similar Questions
medium