Gujarati
2. Electric Potential and Capacitance
easy

A $10\, micro-farad$ capacitor is charged to $500\, V$ and then its plates are joined together through a resistance of $10\, ohm$. The heat produced in the resistance is........$J$

A

$500$

B

$250$

C

$125$

D

$1.25$

Solution

(d) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 10 \times {10^{ – 6}} \times {(500)^2}$$ = 1.25\,J$

Standard 12
Physics

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