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2. Electric Potential and Capacitance
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A $10\, micro-farad$ capacitor is charged to $500\, V$ and then its plates are joined together through a resistance of $10\, ohm$. The heat produced in the resistance is........$J$
A
$500$
B
$250$
C
$125$
D
$1.25$
Solution
(d) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 10 \times {10^{ – 6}} \times {(500)^2}$$ = 1.25\,J$
Standard 12
Physics
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