A 4, ,μ F condenser is charged to 400, V and then its plates are joined through a resistance.

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2. Electric Potential and Capacitance

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A $4\, \,\mu F$ condenser is charged to $400\, V$ and then its plates are joined through a resistance. The heat produced in the resistance is.......$J$

A

$0.16$

B

$0.32$

C

$0.64$

D

$1.28$

Solution

(b) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 4 \times {10^{ – 6}} \times {(400)^2} = 0.32\,J$

Standard 12

Physics

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