A capacitor C is fully charged with voltage V | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\frac{ CV _{0}- q }{ C }=\frac{ q }{ C / 2}=\frac{2 q }{ C }$

$V _{0}=\frac{3 q }{ C } \Rightarrow q =\frac{ CV _{0}}{3}$

$U _{ i }=\frac{1}{2}

Vedclass · Accepted Answer

$0.166$

Vedclass · Answer

$\frac{ CV _{0}- q }{ C }=\frac{ q }{ C / 2}=\frac{2 q }{ C }$

$V _{0}=\frac{3 q }{ C } \Rightarrow q =\frac{ CV _{0}}{3}$

$U _{ i }=\frac{1}{2} CV _{0}^{2}$

$U _{ f }=\frac{\left(\frac{2 CV _{0}}{3}\right)^{2}}{2 C }+\frac{\left(\frac{ CV _{0}}{3}\right)^{2}}{2\left(\frac{ C }{2}\right)}$

$=\frac{1}{2} CV _{0}^{2}\left[\frac{4}{9}+\frac{2}{9}\right]=\frac{1}{2} CV _{0}^{2}\left(\frac{2}{3}\right)$

Heat loss $=\frac{1}{2} CV _{0}^{2}-\left(\frac{2}{3}\right)\left(\frac{1}{2} CV _{0}^{2}\right)$

$=\frac{1}{6} CV _{0}^{2}$

Similar Questions

A $12 \;pF$ capacitor is connected to a $50 \;V$ battery. How much electrostatic energy is stored in the capacitor?

Two insulated metallic spheres of $3\,\mu F$ and $5\,\mu F$ capacitances are charged to $300\, V$ and $500\,V$ respectively. The energy loss, when they are connected by a wire is

The energy of a charged capacitor is given by the expression ($q$= charge on the conductor and $C$ = its capacity)