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7.Alternating Current
medium
A series $R-C$ circuit is connected to an alternating voltage source. Consider two situations
$(a)$ When capacitor is air filled.
$(b)$ When capacitor is mica filled.
Current through resistor is $i$ and voltage across capacitor is $V$ then
A
$V_a=V_b$
B
$V_a< V_b$
C
$V_a > V_b$
D
$i_a >i_b$
(AIPMT-2015)
Solution

Current through resistor, $i$
$=$ Current in the circuit
$=\frac{V_{0}}{\sqrt{R^{2}+X_{C}^{2}}}=\frac{V_{0}}{\sqrt{R^{2}+(1 / \omega C)^{2}}}$
Voltage across capacitor, $V=i X_{C}$
$=\frac{V_{0}}{\sqrt{R^{2}+(1 / \omega C)^{2}}} \times \frac{1}{\omega C}=\frac{V_{0}}{\sqrt{R^{2} \omega^{2} C^{2}+1}}$
As ${C_a} < {C_b}$
$\therefore \,\,{i_a} < {i_b}$ and ${V_a} < {V_b}$
Standard 12
Physics