Gujarati
2. Electric Potential and Capacitance
medium

A $500 \,\mu F$ capacitor is charged at a steady rate of $100\, \mu C/sec$. The potential difference across the capacitor will be $10\, V$ after an interval of.....$sec$

A

$5$

B

$20$

C

$25$

D

$50$

Solution

(d) Charge required to reach the capacitor upto $10\, V$ is
$Q = 500 \times {10^{ – 6}} \times 10 = 5 \times {10^{ – 3}}\,C$
Now required time $ = \frac{{5 \times {{10}^{ – 3}}}}{{100 \times {{10}^{ – 6}}}}$ $= 50\, sec$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.