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14.Probability
easy
A bag contains $30$ balls numbered from $1$ to $30$, one ball is drawn randomly. The probability that number on the ball is multiple of $5$ or $7$ is
A
$\frac{1}{2}$
B
$\frac{1}{3}$
C
$\frac{2}{3}$
D
$\frac{1}{4}$
Solution
(b) Numbers multiple of 5$ = (5,\,\,10,\,\,15,\,\,20,\,\,25,\,\,30)$
Numbers multiple of $7 = (7,\,\,14,\,\,21,\,\,28)$
Multiple of both $ = (0)$;
$P$($5$ or $7$)$ = \frac{{10}}{{30}} = \frac{1}{3}.$
Standard 11
Mathematics