Gujarati
14.Probability
easy

A bag contains $30$ balls numbered from $1$ to $30$, one ball is drawn randomly. The probability that number on the ball is multiple of $5$ or $7$ is

A

$\frac{1}{2}$

B

$\frac{1}{3}$

C

$\frac{2}{3}$

D

$\frac{1}{4}$

Solution

(b) Numbers multiple of 5$ = (5,\,\,10,\,\,15,\,\,20,\,\,25,\,\,30)$

Numbers multiple of $7 = (7,\,\,14,\,\,21,\,\,28)$

Multiple of both $ = (0)$;

$P$($5$ or $7$)$ = \frac{{10}}{{30}} = \frac{1}{3}.$

Standard 11
Mathematics

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