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14.Probability
easy
A bag contains $5$ white, $7$ black and $4$ red balls. Three balls are drawn from the bag at random. The probability that all the three balls are white, is
A
$\frac{3}{{16}}$
B
$\frac{3}{5}$
C
$\frac{1}{{60}}$
D
$\frac{1}{{56}}$
Solution
(d) Required probability $ = \frac{{{}^5{C_3}}}{{{}^{16}{C_3}}} = \frac{{5 \times 4 \times 3}}{{16 \times 15 \times 14}} = \frac{1}{{56}}$.
Standard 11
Mathematics