A bag contains tickets numbered from 1 to 20. | vedclass

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Question

(a) There are $8$ prime numbers $2,\,\,3,\,\,5,\,\,7,\,\,11,\,\,13,\,\,17,\,\,19.$

Hence required probability $ = \frac{{{}^8{C_2}}}{{{}^{20}{C_2}}

Vedclass · Accepted Answer

$\frac{{14}}{{95}}$

Vedclass · Answer

(a) There are $8$ prime numbers $2,\,\,3,\,\,5,\,\,7,\,\,11,\,\,13,\,\,17,\,\,19.$

Hence required probability $ = \frac{{{}^8{C_2}}}{{{}^{20}{C_2}}} = \frac{{8.7}}{{20\,.\,19}} = \frac{{14}}{{95}}$.

A bag contains tickets numbered from $1$ to $20$. Two tickets are drawn. The probability that both the numbers are prime, is

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