Each of the persons mathrm{A} and mathrm{B} i | vedclass

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Question

$C - I \quad\quad'0'$ Head

$\quad\quad\quad\quad\mathrm{T} \mathrm{T} \mathrm{T} \quad\left(\frac{1}{2}\right)^{3}\left(\frac{1}{2}\right)^

Vedclass · Accepted Answer

$\frac{5}{16}$

Vedclass · Answer

$C - I \quad\quad'0'$ Head

$\quad\quad\quad\quad\mathrm{T} \mathrm{T} \mathrm{T} \quad\left(\frac{1}{2}\right)^{3}\left(\frac{1}{2}\right)^{3}=\frac{1}{64}$

$C - II \quad\quad '1'$ head

$\quad\quad\quad\quad\mathrm{HT} \mathrm{T} \quad\left(\frac{3}{8}\right)\left(\frac{3}{8}\right)=\frac{9}{64}$

$C - III \quad\quad'2'$ Head

$\quad\quad\quad\quad\mathrm{H} \mathrm{H} \mathrm{T} \quad\left(\frac{3}{8}\right)\left(\frac{3}{8}\right)=\frac{9}{64}$

$C-IV \quad\quad'3'$ Heads

$\quad\quad\quad\quad\mathrm{H} \mathrm{H} \mathrm{H} \quad\left(\frac{1}{8}\right)\left(\frac{1}{8}\right)=\frac{1}{64}$

Total probability $=\frac{5}{16}$

Each of the persons $\mathrm{A}$ and $\mathrm{B}$ independently tosses three fair coins. The probability that both of them get the same number of heads is :

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