A bag contains $4$ white, $5$ red and $6$ green balls. Three balls are picked up randomly. The probability that a white, a red and a green ball is drawn is

  • A

    $\frac{{15}}{{91}}$

  • B

    $\frac{{30}}{{91}}$

  • C

    $\frac{{20}}{{91}}$

  • D

    $\frac{{24}}{{91}}$

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