A bag contains 4 white, 5 red and 6 green balls. Three balls are picked up randomly. probability tha

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14.Probability

easy

A bag contains $4$ white, $5$ red and $6$ green balls. Three balls are picked up randomly. The probability that a white, a red and a green ball is drawn is

A

$\frac{{15}}{{91}}$

B

$\frac{{30}}{{91}}$

C

$\frac{{20}}{{91}}$

D

$\frac{{24}}{{91}}$

Solution

(d) Required probability $ = \frac{{4\,.\,5\,.\,6}}{{{}^{15}{C_3}}} = \frac{{24}}{{91}}.$

Standard 11

Mathematics

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