A bag contains $5$ distinct Red, $4$ distinct Green and $3$ distinct Black balls. Balls are drawn one by one without replacement,then the probability of getting a particular red ball in fourth draw is-

  • A

    $\frac{1}{12}$

  • B

    $\frac{223}{1188}$

  • C

    $\frac{335}{1320}$

  • D

    $\frac{5}{12}$

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