A ball dropped from top of tower falls first half height of tower in 10 ,s . total time spend by bal

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2.Motion in Straight Line

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A ball dropped from the top of tower falls first half height of tower in $10 \,s$. The total time spend by ball in air is ......... $s$ [Take $g=10 \,m / s ^2$ ]

A$14.14$

B$15.25$

C$12.36$

D$17.36$

Solution

(a)
$\frac{-H}{2}=u t-\frac{1}{2} g \times 10^2$
$\Rightarrow H=g \times 10^2$
$\Rightarrow -H=-\frac{1}{2} g t^2 \quad$ (Full joumey)
$g \times 10^2=\frac{1}{2} g t^2$
$\Rightarrow t^2=200$
$\Rightarrow t=10 \sqrt{2} s$
$\Rightarrow t=10 \times 1.414 s$
$=14.14 s =t$

Standard 11

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A ball dropped from the top of tower falls first half height of tower in $10 \,s$. The total time spend by ball in air is ......... $s$ [Take $g=10 \,m / s ^2$ ]

Solution

Similar Questions

A body is dropped from a height $H$. The time taken to cover second half of the journey is …………

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