A ball is thrown vertically up (taken as +z- axis) from ground. correct momentum-height (p-h) diagra

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4-1.Newton's Laws of Motion

hard

A ball is thrown vertically up (taken as $+z-$ axis) from the ground. The correct momentum-height $(p-h)$ diagram is

(JEE MAIN-2019)

Solution

$\begin{array}{l}
Momentum\,p = mv\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,…\left( 1 \right)\\
and\,for\,motion\,under\,gravity\,\\
h = \frac{{{u^2} – {v^2}}}{{2g}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,…\left( 2 \right)\\
h = \frac{{{u^2} – {p^2}/m}}{{2g}}
\end{array}$

Standard 11

Physics

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(AIPMT-2011)

A ball is thrown vertically up (taken as $+z-$ axis) from the ground. The correct momentum-height $(p-h)$ diagram is

Solution

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