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4-1.Newton's Laws of Motion
easy
A body of mass $M$ hits normally a rigid wall with velocity $V$ and bounces back with the same velocity. The impulse experienced by the body is
A
$MV$
B
$2MV$
C
$4MV$
D
$0$
(AIPMT-2011)
Solution
Impulse = Change in linear momentum
$= MV-(-MV) = 2MV$
Standard 11
Physics
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