4-1.Newton's Laws of Motion
easy

A body of mass $M$ hits normally a rigid wall with velocity $V$ and bounces back with the same velocity. The impulse experienced by the body is

A

$MV$

B

$2MV$

C

$4MV$

D

$0$

(AIPMT-2011)

Solution

Impulse = Change in linear momentum
$= MV-(-MV) = 2MV$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.