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4-1.Newton's Laws of Motion
medium
A ball of weight $0.1\, kg$ coming with speed $30\, m/s$ strikes with a bat and returns in opposite direction with speed $40 \,m/s$, then the impulse is (Taking final velocity as positive)
A
$ - 0.1 \times (40) - 0.1 \times (30)$
B
$0.1 \times (40) - 0.1 \times ( - 30)$
C
$0.1 \times (40) + 0.1 \times ( - 30)$
D
$0.1 \times (40) - 0.1 \times (20)$
Solution
(b)Impulse = change in momentum
$m{v_2} – m{v_1}$= $0.1 \times 40 – 0.1 \times ( – 30)$
Standard 11
Physics
