A ball thrown by one player reaches other in 2, sec . maximum height attained by ball above point of

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3-2.Motion in Plane

medium

A ball thrown by one player reaches the other in $2\, sec$. The maximum height attained by the ball above the point of projection will be about .......... $m$

$2.5$

$5$

$7.5$

$10$

Solution

$\mathrm{t}=\frac{2 \mathrm{u} \sin \theta}{\mathrm{g}} \quad \text { or } \quad 2=\frac{2 \mathrm{u} \sin \theta}{\mathrm{g}}$

$\therefore \mathrm{usin} \theta=\mathrm{g}$

$\therefore \quad \mathrm{h}_{\mathrm{m}}=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{g}}=\frac{\mathrm{g}^{2}}{2 \mathrm{g}}=\frac{\mathrm{g}}{2}=5 \mathrm{m}$

Standard 11

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A ball thrown by one player reaches the other in $2\, sec$. The maximum height attained by the ball above the point of projection will be about .......... $m$

Solution

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