A balloon is moving up in air vertically above a point $A$ on the ground. When it is at a height $h _{1},$ a girl standing at a distance $d$ (point $B$ ) from $A$ (see figure) sees it at an angle $45^{\circ}$ with respect to the vertical. When the balloon climbs up a further height $h _{2},$ it is seen at an angle $60^{\circ}$ with respect to the vertical if the girl moves further by a distance $2.464\, d$ (point $C$ ). Then the height $h _{2}$ is (given tan $\left.30^{\circ}=0.5774\right)$$.......$
$d$
$0.732d$
$1.464d$
$0.464d$
Let $\vec v$ and $\vec a$ denote the velocity and acceleration respectively of a body in one-dimensional motion
A man moves in $x-y$ plane along the path shown. At what point is his average velocity vector in the same direction as his instantaneous velocity vector. The man starts from point $P$.
For any arbitrary motion in space, which of the following relations are true
$(a)$ $\left. v _{\text {average }}=(1 / 2) \text { (v }\left(t_{1}\right)+ v \left(t_{2}\right)\right)$
$(b)$ $v _{\text {average }}=\left[ r \left(t_{2}\right)- r \left(t_{1}\right)\right] /\left(t_{2}-t_{1}\right)$
$(c)$ $v (t)= v (0)+ a t$
$(d)$ $r (t)= r (0)+ v (0) t+(1 / 2)$ a $t^{2}$
$(e)$ $a _{\text {merage }}=\left[ v \left(t_{2}\right)- v \left(t_{1}\right)\right] /\left(t_{2}-t_{1}\right)$
(The 'average' stands for average of the quantity over the time interval $t_{1}$ to $t_{2}$ )
The displacement of a particle from a point having position vector $2 \hat{i}+4 \hat{j}$ to another point having position vector $5 \hat{i}+1 \hat{j}$ is ........ units