A balloon was moving upwards with a uniform velocity of 10, {m} / {s} . An object of finite mass is

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2.Motion in Straight Line

hard

A balloon was moving upwards with a uniform velocity of $10\, {m} / {s}$. An object of finite mass is dropped from the balloon when it was at a height of $75\, {m}$ from the ground level. The height of the balloon from the ground when object strikes the ground was around.(In ${m}$) (Takes the value of $g$ as $10 \,{m} / {s}^{2}$ )

A

$125$

B

$250$

C

$300$

D

$200$

(JEE MAIN-2021)

Solution

$S=u t+\frac{1}{2} a t^2$

$-75=+10 t+\frac{1}{2}(-10) t^2$

$\Rightarrow t=5 sec$

Object takes $t=5 s$ to fall on ground

Height of balloon from ground

$H=75+u t$

$H=75+10 \times 5=125 m$

Standard 11

Physics

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