A bar magnet A of magnetic moment M_A is found to oscillate at a frequency twice that of magnet B of

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5.Magnetism and Matter

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A bar magnet $A$ of magnetic moment $M_A$ is found to oscillate at a frequency twice that of magnet $B$ of magnetic moment $M_B$ when placed in a vibrating magneto-meter. We may say that

${M_A} = 2{M_B}$

${M_A} = 8{M_B}$

${M_A} = 4{M_B}$

${M_B} = 8{M_A}$

Solution

(c)$\nu = \frac{1}{{2\pi }}\sqrt {\frac{{M{B_H}}}{I}} \Rightarrow \nu \propto \sqrt M $
$ \Rightarrow \frac{{{\nu _A}}}{{{\nu _B}}} = \sqrt {\frac{{{M_A}}}{{{M_B}}}} \Rightarrow \frac{2}{1} = \sqrt {\frac{{{M_A}}}{{{M_B}}}} \Rightarrow {M_A} = 4{M_B}$

Standard 12

Physics

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A bar magnet $A$ of magnetic moment $M_A$ is found to oscillate at a frequency twice that of magnet $B$ of magnetic moment $M_B$ when placed in a vibrating magneto-meter. We may say that

Solution

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