A bar magnet of magnetic moment 10^4,J/T is f | vedclass

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Question

(a)Magnetic moment of bar $M = {10^4}\,J/T$
$B = \frac{{{\mu _0}}}{{4\pi }}.\frac{{2\sqrt 2 M}}{{{d^3}}}$
Hence work done $W = \overrightarrow M .\o

Vedclass · Accepted Answer

$0.2$

Vedclass · Answer

(a)Magnetic moment of bar $M = {10^4}\,J/T$
$B = \frac{{{\mu _0}}}{{4\pi }}.\frac{{2\sqrt 2 M}}{{{d^3}}}$
Hence work done $W = \overrightarrow M .\overrightarrow B $
$ = {10^4} 	imes 4 	imes {10^{ - 5}} 	imes \cos {60^o} = 0.2\;J$

A bar magnet of magnetic moment $10^4\,J/T$ is free to rotate in a horizontal plane. The work done in rotating the magnet slowly from a direction parallel to a horizontal magnetic field of $4×10^{-5}\, T$ to a direction $ 60° $ from the field will be.....$ J$

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