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10-1.Thermometry, Thermal Expansion and Calorimetry
hard
A gas follows $VT^2 =$ constant. The coefficient of volume expansion of the gas is
A
$\frac{2}{T}$
B
$ - \frac{2}{T}$
C
$\frac{3}{T}$
D
$ - \frac{3}{T}$
Solution
$V T^2=c$
$V(2 T)+T^2\left(\frac{d V}{d T}\right)=0$
$2 V=-T\left(\frac{dV}{d T}\right)$
$d V=V \gamma d T$
$\frac{d V}{V}=\gamma dT$
$\gamma=\frac{d V}{VdT}$
$\Rightarrow \gamma=-\frac{2}{T}$
Standard 11
Physics
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